Linux下如何查看 CPU 信息, 包括位数和多核信息
By admin
- 3 minutes read - 619 words查看当前操作系统内核信息 # uname -aLinux redcat 2.6.31-20-generic #58-Ubuntu SMP Fri Mar 12 05:23:09 UTC 2010 i686 GNU/Linux
查看当前操作系统发行版信息
#cat /etc/issue
Ubuntu 9.10 n l查看cpu型号# cat /proc/cpuinfo | grep name | cut -f2 -d: | uniq -c
2 Intel(R) Core(TM)2 Duo CPU P8600 @ 2.40GHz
(看到有2个逻辑CPU, 也知道了CPU型号)查看物理cpu颗数
# cat /proc/cpuinfo | grep physical | uniq -c2 physical id : 0
(说明实际上是1颗2核的CPU)查看cpu运行模式
getconf LONG_BIT32(说明当前CPU运行在32bit模式下, 但不代表CPU不支持64bit)查看cpu是否支持64bit# cat /proc/cpuinfo | grep flags | grep ‘ lm ‘ | wc -l2(结果大于0, 说明支持64bit计算. lm指long mode, 支持lm则是64bit)查看cpu信息概要(昨天看aix的时候刚发现的,在ubuntu上竟然也有~):#lscpuArchitecture: i686 #架构686
CPU(s): 2 #逻辑cpu颗数是2
Thread(s) per core: 1 #每个核心线程数是1
Core(s) per socket: 2 #每个cpu插槽核数/每颗物理cpu核数是2
CPU socket(s): 1 #cpu插槽数是1
Vendor ID: GenuineIntel #cpu厂商ID是GenuineIntelCPU family: 6 #cpu系列是6
Model: 23 #型号23
Stepping: 10 #步进是10
CPU MHz: 800.000 #cpu主频是800MHz
Virtualization: VT-x #cpu支持的虚拟化技术VT-x(对此在下一博文中解释下http://hi.baidu.com/sdusoul/blog/item/5d8e0488def3a998a5c272c0.html)
L1d cache: 32K #一级缓存32K(google了下,这具体表示表示cpu的L1数据缓存为32k)
L1i cache: 32K #一级缓存32K(具体为L1指令缓存为32K)L2 cache: 3072K #二级缓存3072K最后来个大而全的:#cat /proc/cpuinfoprocessor : 0
vendor_id : GenuineIntel
cpu family : 6
model : 23
model name : Intel(R) Core(TM)2 Duo CPU P8600 @ 2.40GHz
stepping : 10
cpu MHz : 800.000
cache size : 3072 KB
physical id : 0
siblings : 2
core id : 0
cpu cores : 2
apicid : 0
initial apicid : 0
fdiv_bug : no
hlt_bug : no
f00f_bug : no
coma_bug : no
fpu : yes
fpu_exception : yes
cpuid level : 13
wp : yes
flags : fpu vme de pse tsc msr pae mce cx8 apic mtrr pge mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm pbe nx lm constant_tsc arch_perfmon pebs bts pni dtes64 monitor ds_cpl vmx smx est tm2 ssse3 cx16 xtpr pdcm sse4_1 xsave lahf_lm ida tpr_shadow vnmi flexpriority
bogomips : 4788.60
clflush size : 64
power management:
processor : 1 vendor_id : GenuineIntel cpu family : 6 model : 23 model name : Intel(R) Core(TM)2 Duo CPU P8600 @ 2.40GHz stepping : 10 cpu MHz : 800.000 cache size : 3072 KB physical id : 0 siblings : 2 core id : 1 cpu cores : 2 apicid : 1 initial apicid : 1 fdiv_bug : no hlt_bug : no f00f_bug : no coma_bug : no fpu : yes fpu_exception : yes cpuid level : 13 wp : yes flags : fpu vme de pse tsc msr pae mce cx8 apic mtrr pge mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm pbe nx lm constant_tsc arch_perfmon pebs bts pni dtes64 monitor ds_cpl vmx smx est tm2 ssse3 cx16 xtpr pdcm sse4_1 xsave lahf_lm ida tpr_shadow vnmi flexpriority bogomips : 4787.96 clflush size : 64 power management:
============================================
几个cpu
more /proc/cpuinfo |grep “physical id”|uniq|wc -l
每个cpu是几核(假设cpu配置相同)
more /proc/cpuinfo |grep “physical id”|grep “0”|wc -l
cat /proc/cpuinfo | grep processor
查看物理CPU的个数 #cat /proc/cpuinfo |grep “physical id”|sort |uniq|wc -l
查看逻辑CPU的个数 #cat /proc/cpuinfo |grep “processor”|wc -l
查看CPU是几核 #cat /proc/cpuinfo |grep “cores”|uniq
查看CPU的主频 #cat /proc/cpuinfo |grep MHz|uniq
# uname -a
Linux euis1 2.6.9-55.ELsmp #1 SMP Fri Apr 20 17:03:35 EDT 2007 i686 i686 i386 GNU/Linux
(查看当前操作系统内核信息)
# cat /etc/issue | grep Linux
Red Hat Enterprise Linux AS release 4 (Nahant Update 5)
(查看当前操作系统发行版信息)
# cat /proc/cpuinfo | grep name | cut -f2 -d: | uniq -c
8 Intel(R) Xeon(R) CPU E5410 @ 2.33GHz
(看到有8个逻辑CPU, 也知道了CPU型号)
# cat /proc/cpuinfo | grep physical | uniq -c
4 physical id : 0
4 physical id : 1
(说明实际上是两颗4核的CPU)
# getconf LONG_BIT
32
(说明当前CPU运行在32bit模式下, 但不代表CPU不支持64bit)
# cat /proc/cpuinfo | grep flags | grep ‘ lm ‘ | wc -l
8
(结果大于0, 说明支持64bit计算. lm指long mode, 支持lm则是64bit)
如何获得CPU的详细信息:
linux命令:cat /proc/cpuinfo
用命令判断几个物理CPU,几个核等:
逻辑CPU个数: # cat /proc/cpuinfo | grep “processor” | wc -l
物理CPU个数: # cat /proc/cpuinfo | grep “physical id” | sort | uniq | wc -l
每个物理CPU中Core的个数: # cat /proc/cpuinfo | grep “cpu cores” | wc -l
是否为超线程? 如果有两个逻辑CPU具有相同的”core id”,那么超线程是打开的。
每个物理CPU中逻辑CPU(可能是core, threads或both)的个数: # cat /proc/cpuinfo | grep “siblings”